A compound with molecular mass 180 is acylated with CH 3 COCl to get a compound with molecular mass 390 . The number of amino groups presents per molecule of the former compound is

Step-by-step solution

After acylation the formula will be R - ( NHCOCH 3 ) x . Hence, the change in the molecular mass is calculated as below F o r   1 o n e   N H 2 → 14 + 2 = 16   u n i t s W h e n   I t   t u r n s   i n t o   N H − C O C H 3     ​     → 14 + 1 + 12 + 16 + 12 + 3 = 58   C h a n g e   i n   m a s s ⇒ 58 − 16 = 42 u n i t s .   S o   f o r   e v e r y   N H 2   ,   t h e r e   w i