A ( g ) → 2B ( g ) + C ( g ) is a first order reaction. The initial...

The final pressure of each component can be calculated as follows,

$A ( g ) \to 2B ( g ) + C ( g ) intial80000Attime = t800 - p2pp$

$800 + 2p = 1600$

$2p = 800$

$p = 400$

The first order reaction rate constant can be calculated as follows,

$K = \dfrac{2 . 303}{10}log\dfrac{800}{400} = \dfrac{2 . 303 \times \log 2}{10}$

For $30$ min,

$K = \dfrac{2 . 303}{30}log\dfrac{( 800 )}{( 800 - y )}$

$\dfrac{2 . 303 \times \log 2}{10} = \dfrac{2 . 303}{30}\log \left(\dfrac{800}{800 - y}\right)$

$⇒ \left(\dfrac{800}{800 - y}\right) = 8$

$100 = 800 – y$

$y = 700$

Total pressure after $30$ min

$( 800 – y ) + ( 2y ) + ( y )$

$= 800 + 2y$

$= 800 + 1400$

$= 2200mmHg$