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JEE Main 202313 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
13 April
Shift
Morning Shift
Subject
Chemistry
Chapter
Chemical Kinetics

JEE Main 2023 · 13 April · Morning Shift · Chemistry · Chemical Kinetics

t _ 87 . 5 is the time required for the reaction to undergo 87 . 5...

t87.5{t}_{87 . 5} is the time required for the reaction to undergo 87.587 . 5 % completion and t50{t}_{50} is the time required for the reaction to undergo 5050 % completion. The relation between t87.5{t}_{87 . 5} and t50{t}_{50} for a first order reaction is t87.5=x×t50{t}_{87 . 5} = x \times {t}_{50}
The value of xx is _________ . (Nearest integer)

Correct answer

0

Step-by-step solution

The time for completion of the reaction and concentration of reactant relation is as follows,

At=A0×12.5100=A08[87.5{A}_{t} = {A}_{0} \times \dfrac{12 . 5}{100} = \dfrac{{A}_{0}}{8} [ 87 . 5 % completed ] {A}_{0}\overset{{t}_{1/2}}{\to}\dfrac{{A}_{0}}{2}\overset{{t}_{1/2}}{\to}\dfrac{{A}_{0}}{4}\overset{{t}_{1/2}}{\to}\dfrac{{A}_{0}}{8}{t}_{87 . 5} = 3{t}_{1/2}So, x = 3

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