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JEE Main202228 Jul 2022Evening ShiftChemistryChemical KineticsActual

For a reaction, given below is the graph of lnk vs 1 T . The activation energy for the reaction is equal to____ cal mol - 1 .(Given : R = 2 calK - 1 mol - 1 ) ​​​​​​​

Correct answer

0

Step-by-step solution

Arrhenius suggested an equation which describes rate constant, k as a function of temperature, T. k = Ae - Ea / RT A=frequency factor E a = Activation energy In the Arrhenius equation the factor e - Ea / RT corresponds to the fraction of molecules that have kinetic energy greater than E a lnk = - Ea RT + lnA Y = C + M X On plotting lnk against 1 / T we get a straight line.The slope of the graph gives activation energy and intercept gives frequency factor ​​​​​​​ slope = - Ea R = - Δy Δx Slope = Ea R = 2

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