JEE Main 202623 JanuaryEvening Shift
- Exam
- JEE Main
- Year
- 2026
- Date
- 23 January
- Shift
- Evening Shift
- Subject
- Chemistry
- Chapter
- Classification of Elements and Periodicity in Properties
JEE Main 2026 · 23 January · Evening Shift · Chemistry · Classification of Elements and Periodicity in Properties
Elements X and Y belong to Group 15. The difference between the...
Elements X and Y belong to Group 15. The difference between the electronegativity values of ' X ' and phosphorus is higher than that of the difference between phosphorus and ' Y '. ' X ' \& ' Y ' are respectively
Options
- AN & As
- B
- CBi & N
- DAs & Bi
Correct answer
A. N & As
Step-by-step solution
Group 15 elements have electronegativity values (Pauling scale): N = 3.04, P = 2.19, As = 2.18, Sb = 2.05, Bi = 2.02.
The condition requires: |EN(X) - EN(P)| > |EN(P) - EN(Y)|.
(1) N and As: |3.04 - 2.19| = 0.85 and |2.19 - 2.18| = 0.01. Since 0.85 > 0.01, the condition is satisfied.
(2) As and Sb: |2.18 - 2.19| = 0.01 and |2.19 - 2.05| = 0.14. Since 0.01 < 0.14, it fails.
(3) Bi and N: |2.02 - 2.19| = 0.17 and |2.19 - 3.04| = 0.85. Since 0.17 < 0.85, it fails.
(4) As and Bi: |2.18 - 2.19| = 0.01 and |2.19 - 2.02| = 0.17. Since 0.01 < 0.17, it fails.
The condition requires: |EN(X) - EN(P)| > |EN(P) - EN(Y)|.
(1) N and As: |3.04 - 2.19| = 0.85 and |2.19 - 2.18| = 0.01. Since 0.85 > 0.01, the condition is satisfied.
(2) As and Sb: |2.18 - 2.19| = 0.01 and |2.19 - 2.05| = 0.14. Since 0.01 < 0.14, it fails.
(3) Bi and N: |2.02 - 2.19| = 0.17 and |2.19 - 3.04| = 0.85. Since 0.17 < 0.85, it fails.
(4) As and Bi: |2.18 - 2.19| = 0.01 and |2.19 - 2.02| = 0.17. Since 0.01 < 0.17, it fails.