Electronic configuration of four elements A, B, C and D are given below : (A) 1 ~s^2 2 ~s^2 2 p^3 (B) 1 ~s^2 2 ~s^2 2 p^4 (C) 1 ~s^2 2 ~s^2 2 p^5 (D) 1 ~s^2 2 ~s^2 2 p^2 Which of the following is the correct order of

Correct answer: D. D < A < B < C N:-1 ~s^2 2 ~s^2 2 p^3 (Electronegativity .=3) O:-1 ~s^2 2 ~s^2 2 p^4 (Electronegativity =3.5 ) F:-1 ~s^2 2 ~s^2 2 p^5 (Electronegativity =4 ) C:-1 ~s^2 2 ~s^2 2 p^2 (Electronegativity =2.55 ) Correct order =C B A D

JEE Main 20252 AprilEvening Shift

Exam: JEE Main
Year: 2025
Date: 2 April
Shift: Evening Shift
Subject: Chemistry
Chapter: Classification of Elements and Periodicity in Properties

JEE Main 2025 · 2 April · Evening Shift · Chemistry · Classification of Elements and Periodicity in Properties

Electronic configuration of four elements A, B, C and D are given...

Electronic configuration of four elements

\mathrm{A}, \mathrm{B}, \mathrm{C}

and D are given below :
(A)

1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^3

(B)

1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^4

(C)

1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^5

(D)

1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^2

Which of the following is the correct order of increasing electronegativity (Pauling's scale)?

Options

AA < D < B < C
BA < C < B < D
CA < B < C < D
DD < A < B < C

Correct answer

D. D < A < B < C

Step-by-step solution

\mathrm{N}:-1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^3

(Electronegativity \left.=3\right)

\mathrm{O}:-1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^4

(Electronegativity

=3.5

)

\mathrm{F}:-1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^5

(Electronegativity

=4

)

\mathrm{C}:-1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^2

(Electronegativity

=2.55

)
Correct order

=\mathrm{C} \gt \mathrm{B} \gt \mathrm{A} \gt \mathrm{D}

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