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JEE Main 202331 JanuaryMorning Shift
Exam
JEE Main
Year
2023
Date
31 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Classification of Elements and Periodicity in Properties

JEE Main 2023 · 31 January · Morning Shift · Chemistry · Classification of Elements and Periodicity in Properties

The correct increasing order of the ionic radii is

The correct increasing order of the ionic radii is

Options

  1. ACl−<Ca2+<K+<S2−{Cl}^{-} < {Ca}^{2 +} < {K}^{+} < {S}^{2 -}
  2. BK+<S2−<Ca2+<Cl−{K}^{+} < {S}^{2 -} < {Ca}^{2 +} < {Cl}^{-}
  3. CS2−<Cl−<Ca2+<K+{S}^{2 -} < {Cl}^{-} < {Ca}^{2 +} < {K}^{+}
  4. DCa2+<K+<Cl−<S2−{Ca}^{2 +} < {K}^{+} < {Cl}^{-} < {S}^{2 -}

Correct answer

D. Ca2+<K+<Cl−<S2−{Ca}^{2 +} < {K}^{+} < {Cl}^{-} < {S}^{2 -}

Step-by-step solution

For isoelectronic species, as nuclear charge increases radius decreases. Greater the positive charge, the lesser the size of the ion. Greater the negative charge, the larger the size of an ion.

Ca2+<K+<Cl−<S2−p20191716e18181818{Ca}^{2 +} < {K}^{+} < {Cl}^{-} < {S}^{2 -}p20191716e18181818

So, the correct option is (D).

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