JEE Main202126 Feb 2021Morning ShiftChemistryClassification of Elements and Periodicity in PropertiesActual
Match List- I with List- II . List- I Electronic configuration of elements List- II Δ i H in kJ mol - 1 a 1 s 2 2 s 2 p 801 b 1 s 2 2 s 2 2 p 4 q 899 c 1 s 2 2 s 2 2 p 3 r 1314 d 1 s 2 2 s 2 2 p 1 s 1402 Choose the most appropriate answer from the options given below:
Options
- Aa → q , b → r , c → s , d → p
- Ba → p , b → r , c → s , d → q
- Ca → p , b → s , c → r , d → q
- Da → s , b → p , c → q , d → r
Correct answer
A. a → q , b → r , c → s , d → p
Step-by-step solution
(a) 1 s 2 2 s 2 → Be (b) 1 s 2 2 s 2 2 p 4 → O (c) 1 s 2 2 s 2 2 p 3 → N (d) 1 s 2 2 s 2 2 p 1 → B The ionization enthalpy order is B < Be < O < N Be has more IE compared to B due to extra stability &   N has more IE compared to oxygen due to extra stability Hence, N → 1402   kJ   mol - 1 O → 1314   kJ   mol - 1 B → 801   kJ   mol - 1 Be → 899   kJ   mol - 1