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JEE Main 202621 JanuaryEvening Shift
Exam
JEE Main
Year
2026
Date
21 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Coordination Compounds

JEE Main 2026 · 21 January · Evening Shift · Chemistry · Coordination Compounds

Given below are two statements : Statement I : Crystal Field...

Given below are two statements :
Statement I : Crystal Field Stabilization Energy (CFSE)of[Cr(H2O)6]2+isgreaterthanthatofof \left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+} is greater than that of\left[\mathrm{Mn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$.
Statement II: Potassium ferricyanide has a greater spin-only magnetic moment than sodium ferrocyanide.
In the light of the above statements, choose the correct answer from the options given below :

Options

  1. ABoth Statement I and Statement II are true
  2. BBoth Statement I and Statement II are false
  3. CStatement I is true but Statement II is false
  4. DStatement I is false but Statement II is true

Correct answer

A. Both Statement I and Statement II are true

Step-by-step solution

[Mn(H2O)6]2+⇒\left[\mathrm{Mn}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+} \Rightarrow CFSE value is zero because of d5\mathrm{d}^5 configuration with Weak Field Ligands in coordination number 6 \left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}.<br><br>[Cr(H2O)6]2+⇒CFSE.<br><br>\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+} \Rightarrow \mathrm{CFSE} value is −0.6Δ0-0.6 \Delta_0 because of d4\mathrm{d}^4 configuration with Weak Field Ligands in coordination number 6.

For : K3[Fe(CN)6],μ=1(1+2)=3\mathrm{K}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right], \mu=\sqrt{1(1+2)}=\sqrt{3} B.M.

For : Na4[Fe(CN)6],μ=0\mathrm{Na}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right], \mu=\sqrt{0} B.M.
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