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JEE Main 202524 JanuaryMorning Shift
Exam
JEE Main
Year
2025
Date
24 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Coordination Compounds

JEE Main 2025 · 24 January · Morning Shift · Chemistry · Coordination Compounds

One mole of the octahedral complex compound Co(NH_3)_5 Cl_3 gives 3...

One mole of the octahedral complex compound Co(NH3)5Cl3\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}_3 gives 3 moles of ions on dissolution in water. One mole of the same complex reacts with excess of AgNO3\mathrm{AgNO}_3 solution to yield two moles of AgCl(s)\mathrm{AgCl}_{(\mathrm{s})}. The structure of the complex is:

Options

  1. A[Co(NH3)4Cl2]⋅Cl⋅NH3\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right] \cdot \mathrm{Cl} \cdot \mathrm{NH}_3
  2. B[Co(NH3)3Cl3]⋅2NH3\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_3 \mathrm{Cl}_3\right] \cdot 2 \mathrm{NH}_3
  3. C[Co(NH3)5Cl]Cl2\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_2
  4. D[Co(NH3)4Cl]⋅Cl2⋅NH3\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}\right] \cdot \mathrm{Cl}_2 \cdot \mathrm{NH}_3

Correct answer

C. [Co(NH3)5Cl]Cl2\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_2

Step-by-step solution

[Co(NH3)5Cl]Cl2→[Co(NH3)5Cl]2+( aq. )+2Cl−(aq. )⏟3 ions in water [Co(NH3)5Cl]Cl2( aq. )+2AgNO3( aq. )→[Co(NH3)5Cl](NO3)2( aq. )+2AgCl(s)\begin{array}{l}{\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_2 \rightarrow \underbrace{\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right]^{2+}(\text{ aq. })+2 \mathrm{Cl}^{-}(\text{aq. })}_{3 \text{ ions in water }}} \\ {\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_2(\text{ aq. })+2 \mathrm{AgNO}_3(\text{ aq. }) \rightarrow} {\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right]\left(\mathrm{NO}_3\right)_2(\text{ aq. })+2 \mathrm{AgCl}(\mathrm{s})}\end{array}
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