Consider the following complex ions P = [ FeF 6 ] 3 – , Q = [ V ( H 2 O ) 6 ] 2 + , R = [ Fe ( H 2 O ) 6 ] 2 + The correct order of the complex ions, according to their spin only magnetic moment values (in B.M.) is :

Step-by-step solution

[ FeF 6 ] 3 – : Fe + 3 : [ Ar ] 3 d 5 F : Weak field Ligand No. of unpaired electrons = 5 μ = ( 5 ( 5 + 2 ) ) μ = 35 BM V H 2 O 6 + 2 : V + 2 : 3 d 3 No. of unpaired electrons = 3 μ = 3 ( 3 + 2 ) μ = 15 BM Fe H 2 O 6 + 2 : Fe + 2 : 3 d 6 H 2 O : Weak field Ligand No. of unpaired electrons = 4 μ = 4 ( 4 + 2 ) μ = 24 BM Hence, the answer is option C.