Match List I with List II

LIST-I
Complex LIST-II
Colour

A. $Mg\left({NH}_{4}\right){PO}_{4}$ I. brown

B. ${K}_{3}\left[Co{\left({NO}_{2}\right)}_{6}\right]$ II. white

C. $MnO{\left(OH\right)}_{2}$ III. yellow

D. ${Fe}_{4}{\left[Fe{\left(CN\right)}_{6}\right]}_{3}$ IV. blue

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Question

Match List I with List II

LIST-I Complex		LIST-II Colour
A.	$Mg\left({NH}_{4}\right){PO}_{4}$	I.	brown
B.	${K}_{3}\left[Co{\left({NO}_{2}\right)}_{6}\right]$	II.	white
C.	$MnO{\left(OH\right)}_{2}$	III.	yellow
D.	${Fe}_{4}{\left[Fe{\left(CN\right)}_{6}\right]}_{3}$	IV.	blue

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Quantrex Academy · Accepted Answer

Correct answer: B. A-II, B-III, C-I, D-IV

The formula Mg ( NH _ 4 ) PO _ 4 represents magnesium ammonium phosphate it is white in colour. K _ 3 [Co ( NO _ 2 ) _ 6 ] is known as potassium hexanitritocobaltate(III). It is yellow in colour. The yellow colour is due to the presence of the cobalt ion (Co₃⁺) in the complex, which absorbs certain wavelengths of light and reflects yellow light. MnO (OH) _ 2 is brown in colour. Fe _ 4 [Fe (CN) _ 6 ] _ 3 is blue in colour. Complex Colour Mg( NH _ 4 ) PO _ 4 White K _ 3 [Co ( NO _ 2 ) _ 6 ] Yellow MnO (OH) _ 2 Brown Fe _ 4 [Fe (CN) _ 6 ] _ 3 Blue

Match List I with List II LIST-I Complex LIST-II Colour A. Mg( NH _...

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More from Coordination Compounds

Complex	Colour
$Mg\left({NH}_{4}\right){PO}_{4}$	White
${K}_{3}\left[Co{\left({NO}_{2}\right)}_{6}\right]$	Yellow
$MnO{\left(OH\right)}_{2}$	Brown
${Fe}_{4}{\left[Fe{\left(CN\right)}_{6}\right]}_{3}$	Blue