JEE Main202330 Jan 2023Evening ShiftChemistryCoordination CompoundsActual
1   L , 0 . 02 M solution of Co NH 3 5 SO 4 Br is mixed with 1   L , 0 . 02 M solution of Co NH 3 5 Br SO 4 . The resulting solution is divided into two equal parts X and treated with excess AgNO 3 solution and BaCl 2 solution respectively as shown below: 1   L Solution X + AgNO 3 solution (excess) → Y 1   L Solution X + BaCl 2 solution (excess) → Z The number of moles of Y and Z respe
Options
- A0 . 02 , 0 . 02
- B0 . 01 , 0 . 01
- C0 . 02 , 0 . 01
- D0 . 01 , 0 . 02
Correct answer
B. 0 . 01 , 0 . 01
Step-by-step solution
The number of moles of Co NH 3 5 SO 4 Br = 0 . 02 × 1 = 0 . 02   mol The number of moles of Co NH 3 5 Br SO 4 = 0 . 02 × 1 = 0 . 02   mol The total volume of the solution becomes two Litres after mixing. Following precipitation reactions occur: Co NH 3 5 SO 4 Br + AgNO 3 → AgBr ↓ 0 . 01 mol   excess   0 . 01   mol Co NH 3 5 Br SO 4 + BaCl 2 → BaSO 4 ↓ 0 . 01 mol   excess   0 . 01   mol