The number of paramagnetic species from the following is
${\left[Ni ( CN{)}_{4}\right]}^{2 -}, \left[Ni ( CO{)}_{4}\right], {\left[{NiCl}_{4}\right]}^{2 -}$
${\left[Fe ( CN{)}_{6}\right]}^{4 -}, {\left[Cu{\left({NH}_{3}\right)}_{4}\right]}^{2 +}$
${\left[Fe ( CN{)}_{6}\right]}^{3 -}\text{and}{\left[Fe{\left({H}_{2}O\right)}_{6}\right]}^{2 +}$

Question

The number of paramagnetic species from the following is

${\left[Ni ( CN{)}_{4}\right]}^{2 -}, \left[Ni ( CO{)}_{4}\right], {\left[{NiCl}_{4}\right]}^{2 -}$

${\left[Fe ( CN{)}_{6}\right]}^{4 -}, {\left[Cu{\left({NH}_{3}\right)}_{4}\right]}^{2 +}$

${\left[Fe ( CN{)}_{6}\right]}^{3 -}\text{and}{\left[Fe{\left({H}_{2}O\right)}_{6}\right]}^{2 +}$

The number of paramagnetic species from the following is [Ni ( CN ) _ 4 ] ^ 2 - , [Ni ( CO ) _ 4 ], [ NiCl _ 4 ] ^ 2 -

Quantrex Academy · Accepted Answer

Correct answer: 4

[Ni ( CN ) _ 4 ] ^ 2 - : Ni ^ + 2 = It is diamagnetic as CN - is a strong field ligand and forces electron pairing. [Ni ( CO ) _ 4 ]: Ni = It is diamagnetic as carbonyl group is a strong field ligand and forces electron pairing. [ NiCl _ 4 ] ^ 2 - : Ni ^ 2 + = It is paramagnetic as chloride group is a weak field ligand. [Fe ( CN ) _ 6 ] ^ 4 - : Fe ^ 2 + : - It is diamagnetic as – CN is a strong field ligand which causes pairing of electrons. [Cu ( NH _ 3 ) _ 4 ] ^ + 2 : Cu ^ + 2 ⇒ Here Copper ion has one unpaired electron, thus it is paramagnetic as it is 3 d ^ 9 configuration. [Fe ( CN ) _ 6 ] ^ 3 - : Fe ^ + 3 : It is paramagnetic, here CN ^ - is a strong field ligand [Fe ( H _ 2 O) _ 6 ] ^ 2 + : Fe ^ 2 + : It is paramagnetic, here H _ 2 O , here a weak field ligand

The number of paramagnetic species from the following is [Ni ( CN )...

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