Total number of moles of AgCl precipitated on addition of excess of...

Silver nitrate on reaction of chloride ion gives silver chloride as precipitate. Chloride ions outside of coordination sphere will only give precipitates. Thus,
$\left[Co{\left({NH}_{3}\right)}_{4}{Cl}_{2}\right]Cl ⇒$ Gives $1$ mole $AgCl$
\left[Ni{\left({H}_{2}O\right)}_{6}\right]{Cl}_{2} ⇒$Gives$2$moles$AgCl$<br />\left[Pt{\left({NH}_{3}\right)}_{2}{Cl}_{2}\right] ⇒$ Gives No $AgCl$
\left[Pd{\left({NH}_{3}\right)}_{4}\right]{Cl}_{2} ⇒$Gives$2$moles$AgCl$<br />Total number of moles of$AgCl = 5 mole.