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JEE Main202430 Jan 2024Morning ShiftChemistryd and f Block ElementsActual

Match List-I with List-II List I (Species) List II (Electronic distribution) A. Cr + 2 i. 3 d 8 B. Mn + ii. 3 d 3 4 s 1 C. Ni + 2 iii. . 3 d 4 D. V + iv. 3 d 5 4 s 1 Choose the correct answer from the options given below:

Options

  1. A(A)-I, (B)-II, (C)-III, (D)-IV
  2. B(A)-III, (B) - IV, (C) - I, (D)-II
  3. C(A)-IV, (B)-III, (C)-I, (D)-II
  4. D(A)-II, (B)-I, (C)-IV, (D)-III

Correct answer

B. (A)-III, (B) - IV, (C) - I, (D)-II

Step-by-step solution

Electrons must be removed from the outermost orbital to form an ion. The electronic configurations of the elements are as follows, Cr 24 → [ Ar ] 3 d 5 4 s 1 ; Cr 2 + → [ Ar ] 3 d 4 Mn 25 → [ Ar ] 3 d 5 4 s 2 ; Mn + → [ Ar ] 3 d 5 4 s 1 Ni 28 → [ Ar ] 3 d 8 4 s 2 ; Ni 2 + → [ Ar ] 3 d 8 23 V → [ Ar ] 3 d 3 4 s 2 ; V + → [ Ar ] 3 d 3 4 s 1 Hence option B is the answer.

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