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JEE Main 202429 JanuaryEvening Shift
Exam
JEE Main
Year
2024
Date
29 January
Shift
Evening Shift
Subject
Chemistry
Chapter
d and f Block Elements

JEE Main 2024 · 29 January · Evening Shift · Chemistry · d and f Block Elements

Which of the following acts as a strong reducing agent? (Atomic...

Which of the following acts as a strong reducing agent? (Atomic number : Ce=58,Eu=63Ce = 58, Eu = 63, Gd=64,Lu=71)Gd = 64, Lu = 71 )

Options

  1. ALu3+{Lu}^{3 +}
  2. BGd3+{Gd}^{3 +}
  3. CEu2+{Eu}^{2 +}
  4. DCe4+{Ce}^{4 +}

Correct answer

C. Eu2+{Eu}^{2 +}

Step-by-step solution

A reducing agent is one of the reactants of an oxidation-reduction reaction which reduces the other reactant by giving out electrons to the reactant. If the reducing agent does not pass electrons to other substances in a reaction, then the reduction process cannot occur.

Europium (atomic number 6363) has the electronic configuration \left[Xe\right]4{f}^{7}6{s}^{2}. Itloses twoelectronsfromthe6senergylevelandattainsahighlystable,half−filled. It loses two electrons from the 6s energy level and attains a highly stable, half-filled4{f}^{7}configuration,andhenceitreadilyformsconfiguration, and hence it readily forms{Eu}^{2 +}ion.ion.{Eu}^{2 +}thenchangestothecommonoxidationstatesoflanthanides(+3)then changes to the common oxidation states of lanthanides \left(+ 3\right) and forms Eu3+{Eu}^{3 +}, acting as a strong reducing agent.

{Eu+2→Eu+3+1e−[Xe]4f76s0[Xe]4f66s0\begin{cases}{Eu}^{+ 2} \to & {Eu}^{+ 3} + 1{e}^{-} \\ [ Xe ] 4{f}^{7}6{s}^{0} & [ Xe ] 4{f}^{6}6{s}^{0}\end{cases}

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