Determine the dimensions of the magnetic field B . The relevant...

Using the formula for magnetic force $F = qvB$, the magnetic field $B$ is given by $B = \dfrac{F}{qv}$.

The dimensional formula for force $F$ is $[MLT^{-2}]$.

The dimensional formula for charge $q$ is $[IT]$.

The dimensional formula for velocity $v$ is $[LT^{-1}]$.

Substituting these dimensions into the expression for $B$, we get:

$[B] = \dfrac{[MLT^{-2}]}{[IT][LT^{-1}]}$

$[B] = \dfrac{[MLT^{-2}]}{[IL]}$

$[B] = [MT^{-2}I^{-1}]$