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JEE Main 20149 AprilOnline
Exam
JEE Main
Year
2014
Date
9 April
Mode
Online
Subject
Chemistry
Chapter
Solid State

JEE Main 2014 · 9 April · Online · Chemistry · Solid State

In a face centered cubic lattice atoms A are at the corner points...

In a face centered cubic lattice atoms A are at the corner points and atoms B at the face centered points. If atom B is missing from one of the face centered points, the formula of the ionic compound is :

Options

  1. AA2B3
  2. BAB2
  3. CA5B2
  4. DA2B5

Correct answer

D. A2B5

Step-by-step solution

A atoms at corners =8×18=A(oneatom)= 8 \times \dfrac{1}{8} = A (one atom)

B atom is missing at One face centre then will present at 5 faces

At face centre atom contribute 1/2 part

Number of B atom at Face centre = 5×125 \times \dfrac{1}{2} (B atom)

So formula of compound = A2B5{A}_{2}{B}_{5}
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