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JIPMER 2013
Exam
JIPMER
Year
2013
Subject
Physics
Chapter
Electromagnetic Induction

JIPMER 2013 · Physics · Electromagnetic Induction

In 0.2 s, the current in a coil increases from 2.0 A to 3.0 A. If...

In 0.2 s, the current in a coil increases from 2.0 A to 3.0 A. If inductance of coil is 60 mH, then induced current in external resistance of 3Ω3 \Omega will be

Options

  1. A1 A
  2. B0.5 A
  3. C0.2 A
  4. D0.1 A

Correct answer

D. 0.1 A

Step-by-step solution

Induced emf ∣e∣=Ldidt=(60×10−3)×(3.0−2.0)0.2=60×10−3×10.2=0.3 V\begin{aligned}|e| & =L \frac{d i}{d t}=\left(60 \times 10^{-3}\right) \times \frac{(3.0-2.0)}{0.2} \\ & =\frac{60 \times 10^{-3} \times 1}{0.2}=0.3 \mathrm{~V}\end{aligned} Induced current, ti=eR=0.33=0.1 A\mathrm{t} i=\frac{e}{R}=\frac{0.3}{3}=0.1 \mathrm{~A}
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