A current of 2.5 ~A flows through a coil of inductance 5 H . The magnetic flux linked with the coil is:

Correct answer: B. 12.5 ~Wb According to the question Current I=2.5 ~A and Induction L=5 H Magnetic flux linked with coil is aligned φ& =L I=(5 H) (2.5 ~A)& =12.5 ~Wb aligned

NEET 2013

Exam: NEET
Year: 2013
Subject: Physics
Chapter: Electromagnetic Induction

NEET 2013 · Physics · Electromagnetic Induction

A current of 2.5 ~A flows through a coil of inductance 5 H . The...

A current of

2.5 \mathrm{~A}

flows through a coil of inductance

5 \mathrm{H}

. The magnetic flux linked with the coil is:

Options

A $0.5 \mathrm{~Wb}$
B $12.5 \mathrm{~Wb}$
Czero
D $2 \mathrm{~Wb}$

Correct answer

B. $12.5 \mathrm{~Wb}$

Step-by-step solution

According to the question Current

I=2.5 \mathrm{~A}

and Induction

L=5 \mathrm{H}\therefore

Magnetic flux linked with coil is

\begin{aligned} \phi& =L I=(5 \mathrm{H})\\ (2.5 \mathrm{~A})& =12.5 \mathrm{~Wb} \end{aligned}

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