Consider the following sequence of reactions: Aniline NaNO ₂, HCl , 0-5^ C A Phenol, pH 9-10 B Sn/HCl C + D The products C and D are:

Step-by-step solution

Step 1: Aniline reacts with NaNO ₂ and HCl at 0-5^ C to undergo diazotization, forming benzenediazonium chloride (A). Step 2: Benzenediazonium chloride undergoes an electrophilic substitution (azo coupling) with phenol in a mildly alkaline medium ( pH 9-10 ). The coupling occurs primarily at the para position of phenol, yielding p -hydroxyazobenzene (B). Step 3: Treatment of the azo dye (B) with a strong reducing agent like Sn/HCl results in the complete reductive cleavage of the - N = N - double bond. This cleavag