JEE MainChemistryAmines
Acetanilide is treated with a mixture of concentrated HNO ₃ and concentrated H ₂ SO ₄ to give the major product P. P is then hydrolyzed with acidic water to yield Q. Finally, Q is treated with excess bromine water to give the major product R. Let x be the total number of hydrogen atoms and y be the total number of bromine atoms in a molecule of product R. The value of x y is
Correct answer
8
Step-by-step solution
Nitration of acetanilide with concentrated HNO ₃ and H ₂ SO ₄ yields p -nitroacetanilide (P) as the major product due to the steric hindrance of the bulky acetylamino group at the ortho position. Hydrolysis of P with acidic water removes the acetyl protecting group, producing p -nitroaniline (Q). Treatment of Q with excess bromine water leads to electrophilic aromatic substitution. The - NH ₂ group is strongly activating and ortho/para directing. Since the para position is already occupied by the - NO ₂ group, brom