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MHT CET 202626 AprilMorning Shift
Exam
MHT CET
Year
2026
Date
26 April
Shift
Morning Shift
Subject
Physics
Chapter
Electromagnetic Induction

MHT CET 2026 · 26 April · Morning Shift · Physics · Electromagnetic Induction

In an a.c. generator, a rectangular coil of 1000 turns each having...

In an a.c. generator, a rectangular coil of 10001000 turns each having area 10−2π m2\dfrac{10^{-2}}{\pi}\ \text{m}^2 is rotated at 180180 r.p.m. about an axis perpendicular to a uniform magnetic field of magnitude 22 T. The maximum value of e.m.f. produced will be

Options

  1. A6060 V
  2. B120120 V
  3. C180180 V
  4. D200200 V

Correct answer

B. 120120 V

Step-by-step solution

The maximum e.m.f. produced in an a.c. generator is given by E0=NABωE_0 = NAB\omega

Given:
N=1000N = 1000
A=10−2π m2A = \dfrac{10^{-2}}{\pi}\ \text{m}^2
B=2 TB = 2\ \text{T}
Frequency f=180 r.p.m.=18060 Hz=3 Hzf = 180\ \text{r.p.m.} = \dfrac{180}{60}\ \text{Hz} = 3\ \text{Hz}
Angular velocity ω=2πf=2π×3=6π rad/s\omega = 2\pi f = 2\pi \times 3 = 6\pi\ \text{rad/s}

Substituting the values:
E0=1000×10−2π×2×6πE_0 = 1000 \times \dfrac{10^{-2}}{\pi} \times 2 \times 6\pi

E0=10×12=120 VE_0 = 10 \times 12 = 120\ \text{V}

Answer: 120120 V
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