The magnetic flux through a coil of resistance R changes by an amount Δ in the time Δ t . The total quantity of electric charge (Q ) induced is

Correct answer: C. Q = (Δ )/(R) According to Faraday's law of electromagnetic induction, the magnitude of induced emf is given by |e| = (Δ )/(Δ t) The induced current in the coil of resistance R is I = (|e|)/(R) = (Δ )/(R Δ t) The total quantity of electric charge Q induced in time Δ t is Q = I Δ t = ((Δ )/(R Δ t)) Δ t = (Δ )/(R) Answer: Q = (Δ )/(R)

MHT CET 202621 AprilEvening Shift

Exam: MHT CET
Year: 2026
Date: 21 April
Shift: Evening Shift
Subject: Physics
Chapter: Electromagnetic Induction

MHT CET 2026 · 21 April · Evening Shift · Physics · Electromagnetic Induction

The magnetic flux through a coil of resistance R changes by an...

The magnetic flux through a coil of resistance

R

changes by an amount

\Delta\Phi

in the time

\Delta t

. The total quantity of electric charge (Q

) induced is

Options

A $Q = -\dfrac{\Delta\Phi}{\Delta t} + R$
B $Q = \dfrac{\Delta\Phi}{\Delta t} \times R$
C $Q = \dfrac{\Delta\Phi}{R}$
D $Q = \dfrac{\Delta\Phi}{\Delta t}$

Correct answer

C. $Q = \dfrac{\Delta\Phi}{R}$

Step-by-step solution

According to Faraday's law of electromagnetic induction, the magnitude of induced emf is given by

|e| = \dfrac{\Delta\Phi}{\Delta t}

The induced current in the coil of resistance

R

I = \dfrac{|e|}{R} = \dfrac{\Delta\Phi}{R \Delta t}

The total quantity of electric charge

Q

induced in time

\Delta t

Q = I \Delta t = \left(\dfrac{\Delta\Phi}{R \Delta t}\right) \Delta t = \dfrac{\Delta\Phi}{R}

Answer:

Q = \dfrac{\Delta\Phi}{R}

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