Two coils P and S have a mutual inductance of 5 10⁻³ H . If the current in the primary (P) is I = 10 (100 t) , then the maximum value of e.m.f. induced in S is (in volt)

Step-by-step solution

The induced e.m.f. in the secondary coil is given by: e = -M dI dt Given M = 5 10⁻³ H and I = 10 (100 t) . Differentiating the current with respect to time: dI dt = d dt (10 (100 t)) = 1000 (100 t) Substituting the values into the e.m.f. equation: e = -(5 10⁻³) 1000 (100 t) e = -5 (100 t) The maximum value of the induced e.m.f. corresponds to the maximum magnitude of the cosine function, which is 1 . e_ max = 5 V Answer: 5