The current in a primary coil of a step-down transformer having N_p turns is given by i = i₀ t . The secondary coil of having N_s turns is wound over the primary coil. The emf induced in the secondary is

Step-by-step solution

The current in the primary coil is given by i = i₀ t . The magnetic flux linked with the secondary coil is _s = M i , where M is the mutual inductance between the coils. According to Faraday's law of electromagnetic induction, the induced emf in the secondary coil is given by: e = - d _s dt e = -M di dt Differentiating the expression for current with respect to time t : di dt = d dt (i₀ t) = -i₀ t Substituting this back into the equation for induced emf: e = -M (-i₀ t) e = M i₀ t Answer: M i₀ t