Two coils P and Q are kept near each other. When no current flows through coil P and currrent in coil Q increases at the rate of 10 A/s, the e.m.f. in coil P is 12 mV. When coil Q carries no current and current 1.5 A

Question

Quantrex Academy · Accepted Answer

Correct answer: A. 1.8 mWb

The induced e.m.f. in coil P due to the rate of change of current in coil Q is given by

e_P = M \dfrac{di_Q}{dt}

Substituting the given values,

12 \times 10^{-3} = M \times 10

M = 1.2 \times 10^{-3} \text{ H}

The magnetic flux linked with coil Q when current

i_P

flows through coil P is

\phi_Q = M i_P

\phi_Q = (1.2 \times 10^{-3}) \times 1.5

\phi_Q = 1.8 \times 10^{-3} \text{ Wb} = 1.8 \text{ mWb}

Answer:

1.8 \text{ mWb}

Two coils P and Q are kept near each other. When no current flows...

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