Two coils P and Q are kept near each other. When no current flows through coil P and currrent in coil Q increases at the rate of 10 A/s, the e.m.f. in coil P is 12 mV. When coil Q carries no current and current 1.5 A flows through coil P, the magnetic flux linked with the coil Q is

Step-by-step solution

The induced e.m.f. in coil P due to the rate of change of current in coil Q is given by e_P = M di_Q dt Substituting the given values, 12 10⁻³ = M 10 M = 1.2 10⁻³ H The magnetic flux linked with coil Q when current i_P flows through coil P is _Q = M i_P _Q = (1.2 10⁻³) 1.5 _Q = 1.8 10⁻³ Wb = 1.8 mWb Answer: 1.8 mWb