If _ x a a^x-x^a x^a-a^a =-1 then what is the value of a ?

Step-by-step solution

_ x a a^x-x^a x^a-a^a This is in 0 0 form, by L'Hospital rule _ x a a^x-x^a x^a-a^a = _ x a a^x a-a x^ a-1 a x^ a-1 -0 = a^a a-a^a a^a = a-1 . aligned & a-1=-1 a=0 & a=(e)^0=1 . aligned