If a differentiable function f(x) satisfies _ x -1 f(x)+1 x^2-1 =- 3 2 then what is _ x -1 f(x) equal to?

Step-by-step solution

aligned & _ x -1 f(x)+1 x^2-1 = -3 2 & [ f^ (x) 2 x ]= -3 2 aligned On integrating both sides, aligned & f(x)= -3 2 x^2+c where c= Constant & _ x -1 f(x)= _ x -1 [ -3 2 x^2+c ]= -3 2 aligned