A square loop of side 1   m and resistance 1   Ω is placed in a magnetic field of 0 . 5   T . If the plane of loop is perpendicular to the direction of magnetic field, the magnetic flux through the loop is:

Step-by-step solution

As plane of loop is perpendicular to the direction of magnetic field, therefore direction of area vector will be parallel to magnetic field. Magnetic flux is given by, ϕ = B → · A → = 0 . 5 1 2 cos 0 ° = 0 . 5     Wb