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NEET2008PhysicsElectromagnetic InductionActual

A long solenoid has 500 turns. When a current of 2 ampere is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4 10⁻³ b . The selfinductance of the solenoid is

Options

  1. A4.0 henry
  2. B2.5 henry
  3. C2.0 henry
  4. D1.0 henry

Correct answer

D. 1.0 henry

Step-by-step solution

aligned & N =L i & 500 4 10⁻³=2 L & L=1.0 henry aligned

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