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NEET 2008
Exam
NEET
Year
2008
Subject
Physics
Chapter
Electromagnetic Induction

NEET 2008 · Physics · Electromagnetic Induction

A long solenoid has 500 turns. When a current of 2 ampere is passed...

A long solenoid has 500 turns. When a current of 2 ampere is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4×10−3ωb4 \times 10^{-3} \omega \mathrm{b}. The selfinductance of the solenoid is

Options

  1. A4.0 henry
  2. B2.5 henry
  3. C2.0 henry
  4. D1.0 henry

Correct answer

D. 1.0 henry

Step-by-step solution

Nϕ=Li500×4×10−3=2LL=1.0 henry \begin{aligned}& N \phi=L i \\ & 500 \times4 \times10^{-3}=2 L \\ & L=1.0 \text{ henry } \end{aligned}
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