NEET2008PhysicsElectromagnetic InductionActual
A circular disc of radius 0.2 ~m is placed in a uniform magnetic field of induction 1 ( W b m^2 ) in such a way that its axis makes an angle of 60^ with B . The magnetic flux linked with the disc is
Options
- A0.02 ~Wb
- B0.06 ~Wb
- C0.08 ~Wb
- D0.01 ~Wb
Correct answer
A. 0.02 ~Wb
Step-by-step solution
The magnetic flux passing surface of area A placed in a u field B is given by =B A where is the angle between aligned & Here, =60^ , B= 1 Wb / m ^2, A= (0.2)^2 & Therefore, = 1 (0.2)^2 60^ & =(0.2)^2 1 2 & =0.02 ~Wb & aligned