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NEET2008PhysicsElectromagnetic InductionActual

A circular disc of radius 0.2 ~m is placed in a uniform magnetic field of induction 1 ( W b m^2 ) in such a way that its axis makes an angle of 60^ with B . The magnetic flux linked with the disc is

Options

  1. A0.02 ~Wb
  2. B0.06 ~Wb
  3. C0.08 ~Wb
  4. D0.01 ~Wb

Correct answer

A. 0.02 ~Wb

Step-by-step solution

The magnetic flux passing surface of area A placed in a u field B is given by =B A where is the angle between aligned & Here, =60^ , B= 1 Wb / m ^2, A= (0.2)^2 & Therefore, = 1 (0.2)^2 60^ & =(0.2)^2 1 2 & =0.02 ~Wb & aligned

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