0 .4 g of an organic compound on Kjeldahl’s analysis gave enough ammonia to just neutralize 20 ml of 1N H 2 SO 4 . What is the percentage of nitrogen in the compound?

Step-by-step solution

milli equivalents of NH 3 = milli equivalents of H 2 SO 4 milli moles of NH 3 × 1 = 1 N × 20 ml milli moles of NH 3 = 20 milli moles ∴ mass of N = 2 0 × 14 100 0 = 0.28 ∴ % of N = 0.28 0.4 × 100 = 70 %