NTA Abhyas JEE Main2020ChemistryAminesPractice

Identify 'Z' in the sequence C 6 H 5 NH 2 → 273 K NaNO 2 +HCl X → CuCN Y → Boil H + /H 2 O Z

Options

AC 6 H 5 C H 2 N H 2
BC 6 H 5 C O N H 2
CC 6 H 5 CH 2 OH
DC 6 H 5 C N

Correct answer

B. C 6 H 5 C O N H 2

Step-by-step solution

Here the final product Z is Benzamide which is formed as follows C 6 H 5 NH 2 → 273 K NaNO 2 +HCl C 6 H 5 N 2 + Cl − (X) → CuCN C 6 H 5 CN (Y) → Boil H + /H 2 O C 6 H 5 CONH 2 Benzamide (Z)

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