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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Mathematics
Chapter
Mathematical Reasoning

NTA Abhyas 2020 · Mathematics · Mathematical Reasoning

The negation of p ∧ ( q → ∼ r ) is

The negation of p∧(q→∼r)p ∧ ( q \to ∼ r ) is

Options

  1. A∼p∧(q∧r)∼ p ∧ \left(q ∧ r\right)
  2. Bp∨(q∨r)p ∨ ( q ∨ r )
  3. Cp∨(q∧r)p ∨ ( q ∧ r )
  4. D∼p∨(q∧r)∼ p ∨ ( q ∧ r )

Correct answer

D. ∼p∨(q∧r)∼ p ∨ ( q ∧ r )

Step-by-step solution

∼(p∧(q→∼r))=∼p∨(∼(q→∼r))∼ \left(p ∧ \left(q \to ∼ r\right)\right) = ∼ p ∨ \left(∼ \left(q \to ∼ r\right)\right)

( ∵ ( p ∧ q ) = p ∨ q & ( p \to q ) = p ∧ q )

=∼p∨(q∧∼(∼r))= ∼ p ∨ ( q ∧ ∼ ( ∼ r ) )

= ∼ p ∨ ( q ∧ r )<br />&
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