If p and q are two logical statements, then p ⇒ (q ⇒ p) is...

p ⇒ \left(q ⇒ p\right) ≡ p ∨ \left( q ∨ p\right)
$≡ \left( p ∨ p\right)$ ∨ \left( q\right)$≡ t ∨ \left( q\right)$ ≡ t$<br />hence,$p ⇒ \left(q ⇒ p\right)$is a tautology<br />Now,$p ⇒ \left(p ⇒ q\right) is false when $p$ is true and $q$ is false
$p ⇒ \left(q ∨ p\right)$ ≡ p ∨ \left(p ∨ q\right)$≡ \left( p ∨ p\right)$ ∨ q$<br />$t ∨ q ≡ t$<br />Hence, \left(B\right) is correct.<br />Also,$p ⇒ \left(p ∧ q\right)$is false when$p$is true and$q$is false<br />Also,$p ⇒ \left(p ⇔ q\right) is false when $p$ is true and $q$ is false