Which of the following statements is not a tautology?

$\left(p ∧ q ∧ r\right)$ is subset of $r$, so \left(p ∧ q ∧ r\right)$is a subset of \left( p ∨ q ∨ r\right)$. Hence,& \left(p ∧ q ∧ r\right) ⇒ $\left( p ∨ q ∨ r\right)$ is a tautology.
Similarly, \left(p ∧ q ∧ r\right) ⇒ $\left( \left( p ∧ q\right) ∨ r\right)$ is a tautology because \left(p ∧ q ∧ r\right)is a subset of \left(\left( p ∧ q\right) ∨ r\right)<br />Similarly, \left( p ∧ q ∧ r\right)$is a subset of \left( p ∨ q ∨ r\right)$. Hence,& \left(p ∧ q ∧ r\right)⇒ \left( p ∨ q ∨ r\right) is a tautology
\left(p ∧ q ∧ r\right) ⇒ r$is false if$p$is true,$q$is true and$r$is false. Hence, \left(p ∧ q ∧ r\right) ⇒ r$ is not a tautology