Which of the statements is not a fallacy?

$\left(A\right)$ Option $\left(A\right)$ is true only if $p$ is true and $\left(∼ p ⇒ ∼ q\right)$ is false which can never be possible, hence $\left(A\right)$ is a fallacy
$∴ s \to t$ is a tautology, if $s$ is subset of $t$
$\left(B\right)$\left(p ∧ ∼ q\right)$is a subset of$p,$hence \left(p ∧ ∼ q\right)$⇒ p$is a tautology, hence$∼ \left($\left(p ∧ ∼ q\right)$⇒ p\right)$is a fallacy<br />$\left(C\right)$p$ is a subset of $\left(p ∨ q\right)$, hence $p ⇒ \left(p ∨ ∼ q\right)$ is a tautology, hence $∼$\left(p ⇒ \left(p ∨ ∼ q\right)\right)$is a fallacy<br />$\left(D\right)$Option$\left(D\right)$is the negation of option$\left(A\right)$, hence \left(D\right)$ is a tautology