Which of the statements is not a fallacy?

Step-by-step solution

A Option A is true only if p is true and ∼ p ⇒ ∼ q is false which can never be possible, hence A is a fallacy ∴ s → t is a tautology, if s is subset of t B p ∧ ∼ q is a subset of p, hence p ∧ ∼ q ⇒ p is a tautology, hence ∼ p ∧ ∼ q ⇒ p is a fallacy C p is a subset of p ∨ ~ q , hence p ⇒ p ∨ ∼ q is a tautology, hence ∼ p ⇒ p ∨ ∼ q is a fallacy D Option D is the negation of option A , he