From (6.55 ~g) of aniline, the maximum amount of acetanilide that...

From (6.55 \mathrm{~g}) of aniline, the maximum amount of acetanilide that can be prepared will be ______ (\times 10^{-1} \mathrm{~g}). From (6.55 ~g) of aniline, the maximum amount of acetanilide that can be prepared will be ______ (× 10^ -1 ~g).

Correct answer

Step-by-step solution

93 \mathrm{~g}

aniline form

135 \mathrm{gm}

acetanlide so

\quad 6.55 \mathrm{~g}

anilne form

\frac{135}{93} \times 6.55=9.5

95 \times 10^{-1}

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