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JEE Main 202331 JanuaryEvening Shift
Exam
JEE Main
Year
2023
Date
31 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Amines

JEE Main 2023 · 31 January · Evening Shift · Chemistry · Amines

An organic compound [ A ] ( C _ 4 H _ 11 N) , shows optical...

An organic compound [A](C4H11N)[ A ] \left({C}_{4}{H}_{11}N\right), shows optical activity and gives N2{N}_{2} gas on treatment with HNO2{HNO}_{2}. The compound [A][ A ] reacts with PhSO2Cl{PhSO}_{2}Cl producing a compound which is soluble in KOHKOH. The structure of AA is :An organic compound [ A ] ( C _ 4 H _ 11 N) , shows optical activity and gives N _ 2 gas on treatment with HNO _ 2 .An organic compound [ A ] ( C _ 4 H _ 11 N) , shows optical activity and gives N _ 2 gas on treatment with HNO _ 2 .An organic compound [ A ] ( C _ 4 H _ 11 N) , shows optical activity and gives N _ 2 gas on treatment with HNO _ 2 .An organic compound [ A ] ( C _ 4 H _ 11 N) , shows optical activity and gives N _ 2 gas on treatment with HNO _ 2 .

Options

  1. ALet y = y (x) be the solution of the differential equation, (2 + x)/(y + 1) . (dy)/(dx) =- x , y > 0, y(0) = 1 . If
  2. BLet y = y (x) be the solution of the differential equation, (2 + x)/(y + 1) . (dy)/(dx) =- x , y > 0, y(0) = 1 . If
  3. CLet y = y (x) be the solution of the differential equation, (2 + x)/(y + 1) . (dy)/(dx) =- x , y > 0, y(0) = 1 . If
  4. DLet y = y (x) be the solution of the differential equation, (2 + x)/(y + 1) . (dy)/(dx) =- x , y > 0, y(0) = 1 . If

Correct answer

D. Let y = y (x) be the solution of the differential equation, (2 + x)/(y + 1) . (dy)/(dx) =- x , y > 0, y(0) = 1 . If

Step-by-step solution

Given:
1. Compound is optically active ⇒⇒ contains chiral carbon/Nitrogen.
2. Compound liberates N2{N}_{2} gas with HNO2⇒{HNO}_{2} ⇒ It is primary amine
3. Compound reacts with PhSO2Cl{PhSO}_{2}Cl and the product is soluble in KOHKOH - It is a primary amine.

Option (A) and (D) are primary amines. But only option (D) satisfy all the above conditions.

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