The negation of the Boolean expression ~ q ∧ p ⇒ ~ p ∨ q is logically equivalent to

Step-by-step solution

To find negation of ( ~ q ∧ p → ~ p ∨ q Let ~ q ∧ p = A & ~ p ∨ q = B ~ A → B = ~ ~ A ∨ B = A ∧ ~ B Using above formula be get ~ q ∧ p ∧ ~ ~ p ∨ q = ~ q ∧ p ∧ p ∧ ~ q = A ∧ A = A = ~ q ∧ p = p ∧ ~ q or ~ p → q