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JEE Main 202225 JuneMorning Shift
Exam
JEE Main
Year
2022
Date
25 June
Shift
Morning Shift
Subject
Mathematics
Chapter
Mathematical Reasoning

JEE Main 2022 · 25 June · Morning Shift · Mathematics · Mathematical Reasoning

Consider the following two propositions : P _ 1 : ~ (p → ~ q) P _ 2...

Consider the following two propositions :
P1{P}_{1}:  (p→ q)~ \left(p \to ~ q\right)
P2{P}_{2}: \left(p ∧ ~ q\right) ∧ \left(\left(~ p\right) ∨ q\right)</p><p>Iftheproposition</p><p>If the propositionp \to \left(\left(~ p\right) ∨ q\right) is evaluated as FALSE, then

Options

  1. AP1{P}_{1} is TRUE and P2{P}_{2} is FALSE
  2. BP1{P}_{1} is FALSE and P2{P}_{2} is TRUE
  3. CBoth P1{P}_{1} and P2{P}_{2} are FALSE
  4. DBoth P1{P}_{1} and P2{P}_{2} are TRUE

Correct answer

C. Both P1{P}_{1} and P2{P}_{2} are FALSE

Step-by-step solution

pp qq  p~ p  q~ q  p∨q~ p ∨ q p→( p∨q)p \to \left(~ p ∨ q\right) p→ qp \to ~ q  (p→ q)~ \left(p \to ~ q\right) p∧ qp ∧ ~ q \left(p ∧ ~ q\right) ∧ \left(\left(~ p\right) ∨ q\right)</td></tr><tr><td></td> </tr> <tr> <td>T</td><td></td> <td>T</td><td></td> <td>F</td><td></td> <td>F</td><td></td> <td>T</td><td></td> <td>T</td><td></td> <td>F</td><td></td> <td>T</td><td></td> <td>F</td><td></td> <td>F</td></tr><tr><td></td> </tr> <tr> <td>T</td><td></td> <td>F</td><td></td> <td>F</td><td></td> <td>T</td><td></td> <td>F</td><td></td> <td>F</td><td></td> <td>T</td><td></td> <td>F</td><td></td> <td>T</td><td></td> <td>F</td></tr><tr><td></td> </tr> <tr> <td>F</td><td></td> <td>T</td><td></td> <td>T</td><td></td> <td>F</td><td></td> <td>T</td><td></td> <td>T</td><td></td> <td>T</td><td></td> <td>F</td><td></td> <td>F</td><td></td> <td>F</td></tr><tr><td></td> </tr> <tr> <td>F</td><td></td> <td>F</td><td></td> <td>T</td><td></td> <td>T</td><td></td> <td>T</td><td></td> <td>T</td><td></td> <td>T</td><td></td> <td>F</td><td></td> <td>F</td><td></td> <td>F</td></tr></tbody></table><p></td> </tr> </tbody></table><p>p \to \left(~ p ∨ q\right)isisFwhenwhenpistrueis trueqisfalsefromthetable.</p><p>Hence,is false from the table.</p><p>Hence,{P}_{1} \text{ and } {P}_{2} both are false

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