If p ⇒ (q ∨ r) is False , then the truth values of p, q, r are...

We know that the conditional statement $a ⇒ b$ is $False$ only when $a$ is $False$ and $b$ is $True .$

Hence, $p ⇒ ( q ∨ r ) : False$ when $p: True; q ∨ r: False$

Again, we know that $a ∨ b$ is $False$ when both $a \text{ and } b$ are false.

Hence, $p: True; q: False; r: False .$