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A student has planned to prepare acetanilide from aniline using acetic anhydride. The student has started from 9.3 g of aniline. However, the student has managed to obtain 11 g of dry acetanilide. The % yield of this reaction is :-

Options

  1. A59.5 %
  2. B72.5 %
  3. C97.5 %
  4. D81.5 %

Correct answer

D. 81.5 %

Step-by-step solution

Molar mass of aniline ( C₆H₅NH₂ ) = 93 g/mol. Moles of aniline = 9.3/93 = 0.1 mol. From the reaction, theoretical yield of acetanilide = 0.1 mol. Molar mass of acetanilide ( C₆H₅NHCOCH₃ ) = 135 g/mol. Theoretical mass = 0.1 × 135 = 13.5 g. Percentage yield = (11/13.5) × 100 = 81.5%

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