JEE Main 202624 JanuaryEvening Shift
- Exam
- JEE Main
- Year
- 2026
- Date
- 24 January
- Shift
- Evening Shift
- Subject
- Chemistry
- Chapter
- Amines
JEE Main 2026 · 24 January · Evening Shift · Chemistry · Amines
A student has planned to prepare acetanilide from aniline using...
A student has planned to prepare acetanilide from aniline using acetic anhydride. The student has started from 9.3 g of aniline. However, the student has managed to obtain 11 g of dry acetanilide. The % yield of this reaction is :-
Options
- A59.5 %
- B
- C
- D
Correct answer
D.
Step-by-step solution
Molar mass of aniline () = 93 g/mol.
Moles of aniline = 9.3/93 = 0.1 mol.
From the reaction, theoretical yield of acetanilide = 0.1 mol.
Molar mass of acetanilide () = 135 g/mol.
Theoretical mass = 0.1 × 135 = 13.5 g.
Percentage yield = (11/13.5) × 100 = 81.5%
Moles of aniline = 9.3/93 = 0.1 mol.
From the reaction, theoretical yield of acetanilide = 0.1 mol.
Molar mass of acetanilide () = 135 g/mol.
Theoretical mass = 0.1 × 135 = 13.5 g.
Percentage yield = (11/13.5) × 100 = 81.5%