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JEE Mathematics 2009 previous year questions with solutions

53 JEE Mathematics questions from 2009 in the Quantrex bank. Featured questions below open unique solution pages. Browse by chapter on JEE Mathematics.

53 questions2009
1

For the function f(x)=x 1 x , x 1 ,

JEE Advanced 2009 Application of Derivatives Solution
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2

The maximum value of the function f(x)=2 x^3-15 x^2+36 x-48 on the set A= x x^2+20 9 x is

JEE Advanced 2009 Application of Derivatives Solution
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3

Let p(x) be a polynomial of degree 4 having extremum at x=1,2 and _ x 0 [1+ p(x) x^2 ]=2 . Then, the value of p(2) is

JEE Advanced 2009 Application of Derivatives Solution
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4

Area of the region bounded by the curve y=e^x and lines x=0 and y=e is

JEE Advanced 2009 Area Under Curves Solution
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5

The area of the region bounded by the parabola (y-2)^2=x-1 , the tangent to the parabola at the point (2,3) and the x -axis is

JEE Main 2009 Area Under Curves Solution
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6

The centres of two circles C₁ and C₂ each of unit radius are at a distance of 6 units from each other. Let P be the mid-point of the line segment joining the ce

JEE Advanced 2009 Circle Solution
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7

Tangents drawn from the point P(1,8) to the circle x^2+y^2-6 x-4 y-11=0 touch the circle at the points A and B . The equation of the circumcircle of P A B is

JEE Advanced 2009 Circle Solution
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8

If P and Q are the points of intersection of the circles x^2+y^2+3 x+7 y+2 p-5=0 and x^2+y^2+2 x+2 y-p^2=0 , then there is a circle passing through P, Q and (1,

JEE Main 2009 Circle Solution
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9

Let z= +i . Then, the value of _ m=1 ¹⁵ Im (z^ 2 m-1 ) at =2^ is

JEE Advanced 2009 Complex Number Solution
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10

Let z=x+i y be a complex number, where x and y are integers. Then, the area of the rectangle whose vertices are the roots of the equation z z ^3+ z z^3=350 is

JEE Advanced 2009 Complex Number Solution
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11

Let f(x)=x|x| and g(x)= x . Statement-1 : gof is differentiable at x=0 and its derivative is continuous at that point. Statement-2 : gof is twice differentiable

JEE Main 2009 Continuity and Differentiability Solution
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12

If I_n= _ - ^ n x (1+ ^x ) x d x ; n=0,1,2 , , then

JEE Advanced 2009 Definite Integration Solution
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13

Let f: R R be a continuous function, which satisfies f(x)= ₀^x f(t) d t . Then, the value of f( 5) is

JEE Advanced 2009 Definite Integration Solution
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14

Let f be a non-negative function defined on the interval [0,1] . If ₀^x 1- f^ (t) ^2 d t= ₀^x f(t) d t, 0 x 1 and f(0)=0 , then

JEE Advanced 2009 Definite Integration Solution
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15

Match the statements/expressions in Column I with the open intervals in Column II.

JEE Advanced 2009 Definite Integration Solution
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16

Let (x, y, z) be points with integer coordinates satisfying the system of homogeneous equations 3 x-y-z=0,-3 x+z=0,-3 x+2 y+z=0 . Then, the number of such point

JEE Advanced 2009 Determinants Solution
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17

Paragraph: Let A be the set of all 3 3 symmetric matrices all of whose entries are either 0 or 1 . Five of these entries are 1 and four of them are 0 . Question

JEE Advanced 2009 Determinants Solution
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18

Paragraph: Let A be the set of all 3 3 symmetric matrices all of whose entries are either 0 or 1 . Five of these entries are 1 and four of them are 0 . Question

JEE Advanced 2009 Determinants Solution
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19

Let a, b, c be such that b(a+c) 0 . If | array ccc a & a+1 & a-1 -b & b+1 & b-1 c & c-1 & c+1 array |+ | array ccc a+1 & b+1 & c-1 a-1 & b-1 & c+1 (-1)^ n+2 a &

JEE Main 2009 Determinants Solution
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20

Let A and B denote the statements A: + + =0 B: + + =0 If ( - )+ ( - )+ ( - )=- 3 2 , then

JEE Main 2009 Determinants Solution
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21

If the function f(x)=x^3+e^ x 2 and g(x)=f⁻¹(x) , then the value of g^ (1) is

JEE Advanced 2009 Differentiation Solution
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22

Let y be an implicit function of x defined by x^ 2 x -2 x^x y-1=0 . Then y^ (1) equals

JEE Main 2009 Differentiation Solution
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23

The normal at a point P on the ellipse x^2+4 y^2=16 meets the x -axis at Q . If M is the mid-point of the line segment P Q , then the locus of M intersects the

JEE Advanced 2009 Ellipse Solution
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24

An ellipse intersects the hyperbola 2 x^2-2 y^2=1 orthogonally. The eccentricity of the ellipse is reciprocal to that of the hyperbola. If the axes of the ellip

JEE Advanced 2009 Ellipse Solution
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